Rob W Posted September 21, 2018 Report Share Posted September 21, 2018 I have a Ballenger AFR 500 Wideband here to install. Can anyone tell me what this should look like in the Cal Table Lambbda (.618-1.098) = 0.618 +V out x 0.096 It has a linear output where 0v is equal to .618 and 5v is 1.098 So is it simply a matter of Input Value A =0v, Output =.618 : Input B 5v, Output 1.098 Quote Link to comment Share on other sites More sharing options...
Adamw Posted September 22, 2018 Report Share Posted September 22, 2018 5 hours ago, Rob W said: So is it simply a matter of Input Value A =0v, Output =.618 : Input B 5v, Output 1.098 Yep, use cal 4,5 or 6 and that’s all you need. Rob W 1 Quote Link to comment Share on other sites More sharing options...
Rob W Posted September 22, 2018 Author Report Share Posted September 22, 2018 Thanks Adam. Quote Link to comment Share on other sites More sharing options...
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